10x=2.25x^2

Solution for 10x=2.25x^2 equation:

10x=2.25x^2

We move all terms to the left:

10x-(2.25x^2)=0

We get rid of parentheses

-2.25x^2+10x=0

a = -2.25; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-2.25)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-2.25}=\frac{-20}{-4.5}
=4+1/2.25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-2.25}=\frac{0}{-4.5}
=0
$